What does it mean to say that an object decelerates?

  • Thread starter Thread starter wein7145
  • Start date Start date
  • Tags Tags
    Mean
Click For Summary
SUMMARY

The discussion clarifies the concept of deceleration in physics, emphasizing that deceleration refers to a reduction in speed rather than a decrease in acceleration. Participants noted that acceleration is a vector quantity measured in meters per second squared (m/s²), while speed is a scalar quantity measured in meters per second (m/s). The term 'deceleration' is often misused and can introduce ambiguity, as it is not synonymous with negative acceleration. The conversation underscores the importance of understanding these distinctions for accurate application in physics.

PREREQUISITES
  • Understanding of vector and scalar quantities in physics
  • Familiarity with acceleration and its measurement in m/s²
  • Knowledge of basic kinematic equations, specifically v(t) = v0 + a·t
  • Concept of velocity and its relationship with time
NEXT STEPS
  • Study the differences between scalar and vector quantities in physics
  • Learn how to apply kinematic equations in various scenarios
  • Explore the implications of negative acceleration in different contexts
  • Investigate the historical and technical usage of the term 'deceleration' in physics literature
USEFUL FOR

Students of physics, educators teaching kinematics, and anyone seeking to clarify concepts of acceleration and deceleration in physical systems.

wein7145
Messages
19
Reaction score
0

Homework Statement


What does it mean to say that an object undergoes a deceleration? Can this term be used without ambiguity? Edit (That was straight from the book poorly written: Should say object decelerates not undergoes a deceleration)

Homework Equations


v(t)=v0+a⋅t

The Attempt at a Solution


Deceleration means less acceleration or going slower. But this can be ambiguous in terms of positive and negative: it can be a little less positive but still positive or a little less negative but still negative this same problem happens in velocity.

I just want a second opinion on this the textbook does say something about asking questions and making conclusions that better a larger system of Physics. This larger teamwork based system of Physics is how it all works at our jobs apparently which is why we are learning this way; to be better prepared for our future jobs. It makes sense I can't just make up laws or rules without knowing what other people agree on/what the real accepted laws or rules are.
 
Physics news on Phys.org
Do you have any reason to believe that an object which goes from an acceleration of 10 m/s^2 to 9 m/s^2 has decelerated? After all, it's still speeding up.
 
wein7145 said:
Deceleration means less acceleration or going slower.
Those are two different things. One is right, one is wrong.
 
  • Like
Likes wein7145 and CWatters
Do you have any reason to believe that an object which goes from an acceleration of 10 m/s^2 to 9 m/s^2 has decelerated? After all, it's still speeding up.
I'm pretty sure that it decelerated by 1m/s yes it still is positive but decelerated. 10m/s to 11m/s is acceleration by 1m/s.

Those are two different things. One is right, one is wrong.
Oh...which one is right the book says something about acceleration is positive if velocity over time is more positive or less negative than initial velocity and acceleration is negative (deceleration?) if velocity over time is more negative or less positive than initial velocity
 
wein7145 said:
I'm pretty sure that it decelerated by 1m/s yes it still is positive but decelerated. 10m/s to 11m/s is acceleration by 1m/s.
Read axmls' post more carefully. 10m/s is a speed; axmls wrote 10m/s2, an acceleration.
wein7145 said:
Oh...which one is right the book says something about acceleration is positive if velocity over time is more positive or less negative than initial velocity and acceleration is negative (deceleration?) if velocity over time is more negative or less positive than initial velocity
No, I don't think deceleration is the same as negative acceleration. It's tricky because there's a difference between everyday usage and technical definition.
In physics, acceleration is a vector. Expressed in a co-ordinate system, it may be negative with respect to an axis. If an object is moving in the positive x direction with a negative acceleration then it is slowing down. If it is moving in the negative x direction with a negative acceleration it is getting faster.
The term 'deceleration' has no use here. All changes in velocity (including changes of direction) are accelerations. It is only used, as far as I am aware, in a scalar sense. That is, as a reduction in speed.
 
  • Like
Likes wein7145
You are using the wrong dimensions for acceleration, insted of m/s, acceleration is measured by m/s^2. An acceleration is a rate of change of velocity, in relation to time. In some time to there is a velocity vo, and for a time later on t1 there is a velocity v1. The average acceleration of an object is defined as (v1-vo ) / (t1-vo). In that way, if v1>vo, there is a positive acceleration. If v1<vo, there is a negative acceleration. Depending if you're dealing with scalars or vectors, this can mean different things sometimes. But dealing with scalars, if there is a positive acceleration, than the object gains speed. If there is a negative acceleration and the object looses speed, than it's called a deceleration.
 
  • Like
Likes wein7145
OH Whoops yeah that's right m/s is speed and m/s^2 is acceleration. But back to the main question
What does it mean to say that an object undergoes a deceleration? Can this term be used without ambiguity? Edit (That was straight from the book poorly written: Should say object decelerates not undergoes a deceleration)
The term 'deceleration' has no use here.
Maybe that is what the book is trying to teach I understand that. Which means there is ambiguity yes that answers part of the question.
If there is a negative acceleration and the object looses speed, than it's called a deceleration.
That answers the other part of the question. Thanks for the help.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 22 ·
Replies
22
Views
858
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 2 ·
Replies
2
Views
10K
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K