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A certain crystal has a planar spacing of .25nm. What energies are necessary to observe up to three interference (diffraction) maxima for a)electrons and b)neutrons?
To observe up to three interference maxima in a crystal with a planar spacing of 0.25 nm, specific energies for electrons and neutrons must be calculated using Bragg's Law. For electrons, the required energies are approximately 1.5 keV, 3.0 keV, and 4.5 keV, while for neutrons, the energies needed are around 0.025 eV, 0.050 eV, and 0.075 eV. These calculations are based on the relationship between wavelength, planar spacing, and the angles of diffraction.
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