What Equation Determines the Velocity for a Basketball Shot?

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SUMMARY

The discussion focuses on determining the velocity required for a basketball shot under ideal conditions, specifically with an initial height of 6 feet, a trajectory angle of 45 degrees, a range of 14 feet, and a hoop height of 10 feet. The relevant kinematic equations of motion are highlighted, including the equations for vertical and horizontal motion: y(t) = y0 + v0 sin(a) t - (1/2) g t² and x(t) = x0 + v0 cos(a) t. The user is guided to understand the components of vertical velocity (v_y) and how to apply these equations to solve for the unknown initial vertical velocity.

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  • Basic grasp of gravitational acceleration (g = 9.81 m/s²)
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Homework Statement


I don't know what equation to use. i am trying to find out the velocity need to make a shot. the conditions are ideal.
initial height: 6 feet
initial vertical velocity:unknown
angle of trajectory: 45 degrees
range: 14 feet
time:2 seconds
basketball hoop height: 10 feet

Homework Equations





The Attempt at a Solution


 
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Leonof said:

Homework Statement



I don't know what equation to use. i am trying to find out the velocity need to make a shot. the conditions are ideal.
initial height: 6 feet
initial vertical velocity:unknown
angle of trajectory: 45 degrees
range: 14 feet
time:2 seconds
basketball hoop height: 10 feet

Welcome to the PF. The Relevant Equations are the kinematic equations of motion for a constant acceleration (the acceleration due to gravity). Can you list those for us?

v_y(t) = _________

y(t) = __________

And you have a constant velocity in the x direction, so you can write:

x(t) = __________
 
xt=x0 + v0 cos(a) t
y(t) = y0 + v0 sin(a) t - (1/2) g t^2

i don't understand what is meant by v_y(t)
 
Leonof said:
xt=x0 + v0 cos(a) t
y(t) = y0 + v0 sin(a) t - (1/2) g t^2

i don't understand what is meant by v_y(t)

Good start. v_y is shorthand for the velocity in the y direction. Written more clearly in Latex:

v_y
 
v_y=vsin0-(gx/vcos0)
 
so 14+4cos45*2=18.2
-> 4sin45-(g*18.2/4cos45)?
 

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