What figure do these 3D vectors make?

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SUMMARY

The vertices A(-8, 4, -2), B(-6, 3, 5), and C(-10, 5, -9) form a collinear figure in three-dimensional space. The calculations for the magnitudes of the vectors |AB|, |BC|, and |CA| yielded |AB|=3√6, |BC|=6√6, and |CA|=3√6. The conclusion drawn from the calculations indicates that point A lies on the line connecting points B and C, confirming that the three points are linearly interdependent and thus do not form a polygonal figure.

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Homework Statement


The vertices of a figure are given by A(-8, 4, -2), B(-6, 3, 5), and C(-10, 5, -9). What type of figure is ABC? Why?

Homework Equations


pythagorean theorem: |AB|=√(x^2+y^2+z^2)

The Attempt at a Solution


I first found the vector AB, BC, and CA by subtracting the components of the vectors.
Then I calculation the magnitude of |AB|, |BC|, and |CA| using the pythagorean theorem.
I got this |AB|=3√6 |BC|=6√6 and |CA|=3√6
According to my calculation, point A is on the line connecting points B and C, so the 3 points are collinear and form a line.

But the answer seems wrong since they are asking for a type of a figure.
 
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The vectors are indeed linearly interdependent, your conclusion is correct.
 

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