What force is needed to lift a wheel over a bump with given mass and radius?

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Homework Help Overview

The problem involves determining the force required to lift a wheel of mass 2kg and radius R over a step of height h, with the relationship that R is twice as large as h. The context includes considerations of torque and moment of inertia.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of torque and moment of inertia, with questions about the choice of pivot point and the nature of forces acting on the wheel as it moves over the bump.

Discussion Status

Guidance has been offered regarding the pivot point for torque calculations and the forces involved. Participants are exploring the relationship between the applied force and gravitational torque, while clarifying the role of moment of inertia in this context.

Contextual Notes

There is uncertainty regarding the angle of the wheel as it spins over the bump and how this affects the perpendicularity of the applied force. Participants are also considering the minimum force needed to just lift the wheel over the bump.

Julia123
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Homework Statement


The question is as follows:
How much force should I apply if i want to have a wheel of mass 2kg and radius R to pass over a step with height h, where R is twice as big as h.
I attached a picture of the problem for reference.
wheel over bump.png

Homework Equations


I am not sure but I think I should be using torque and possibly moment of Inertia to solve this problem.

The Attempt at a Solution


I don't know how to approach the problem and would really appreciate a nudge in the right direction. Thank you in advance for any and all help!
 
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Here's a nudge: Torque is the way to go. What will you take as your pivot point for calculating torque?
 
The pivot point must be the corner of the step right? But what do I do from there? How can I know that the force is perpendicular if the wheel is spinning over the bump and the angle is changing?
 
Julia123 said:
The pivot point must be the corner of the step right?
That works.

Julia123 said:
How can I know that the force is perpendicular if the wheel is spinning over the bump and the angle is changing?
The applied force is horizontal, per the diagram. What other forces act to create a torque about the pivot?
 
the force of gravity also works to create a torque about the pivot. The moment of inertia works against the angular acceleration of the wheel. Do I have to account for both of these things in the torque equation?
 
Julia123 said:
the force of gravity also works to create a torque about the pivot.
Good. In what direction is the torque due to gravity? The applied force must at least balance that torque in order to lift up the wheel.

Julia123 said:
The moment of inertia works against the angular acceleration of the wheel. Do I have to account for both of these things in the torque equation?
No, forget about angular acceleration. Just consider torque. You are looking for the minimum applied force to just barely lift the thing over the bump.
 

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