What Force is Needed to Reach a New Position in Physics?

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The discussion focuses on calculating the force F2 acting on a 2.50kg object moving along the x-axis at 160m/s, subjected to an initial force F1 of 15N in the y direction for 3.00 seconds. Using Newton's second law (F = ma) and standard constant acceleration equations, participants aim to determine the value of F2 after the object reaches the coordinates x=4.80m and y=10.8m. The application of these principles is essential for solving the problem accurately.

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A 2.50kg object is moving along the x-axis at 160m/s. as it passes the origin, two forces F1 and F2 are applied, both in the y direction f1=15N in the j direction. The forces are applied for 3.00s after which the object is at the point x=4.80m y=10.8m. Find f2.

can anyone figure out how to do this?
 
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Welcome to PF!

Hi sheers! Welcome to PF! :smile:
sheers said:
A 2.50kg object is moving along the x-axis at 160m/s. as it passes the origin, two forces F1 and F2 are applied, both in the y direction f1=15N in the j direction. The forces are applied for 3.00s after which the object is at the point x=4.80m y=10.8m. Find f2.

can anyone figure out how to do this?

yes, you can :wink:

use good ol' Newton's second law (F = ma), and the standard constant acceleration equations …

what do you get? :smile:
 

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