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phyiscsormath
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What gives satellite a tangential velocity?
B What gives satellites their tangential velocity?
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AI Thread Summary
Satellites achieve tangential velocity primarily through a two-phase launch process. Initially, they are launched vertically to penetrate the lower atmosphere, followed by a horizontal acceleration to reach the required speed for orbit. This horizontal motion is crucial for maintaining a stable orbit around the Earth. Understanding this process is essential for comprehending how satellites remain in space for extended periods. The mechanics of this launch strategy highlight the complexities of orbital dynamics.
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phyiscsormath said:
I guess the short answer is "that's rocket science"!
Basically the satellite is launched vertically to get through the lower part of the atmosphere, but then accelerates horizontally to achieve the necessary tangential velocity.
There's a good explanation here, for example:
https://www.scienceabc.com/nature/u...into-orbit-and-kept-up-there-for-so-long.html
- #3
phyiscsormath
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Thank you!PeroK said:
I guess the short answer is "that's rocket science"!
Basically the satellite is launched vertically to get through the lower part of the atmosphere, but then accelerates horizontally to achieve the necessary tangential velocity.
There's a good explanation here, for example:
https://www.scienceabc.com/nature/u...into-orbit-and-kept-up-there-for-so-long.html
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire.
We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges.
By using the Lorenz gauge condition:
$$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$
we find the following retarded solutions to the Maxwell equations
If we assume that...
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Is it true that in any mechanical set-up, it is possible to predict the nature of Normal Reaction ( magnitude, direction, etc. ) without solving through the dynamical equations of motion and constraints for the set-up as Normal Reaction is completely unknown? I mean is it true that we can explain NR intuitively beforehand?
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