What Group Preserves the Invariance of E^2 - B^2 in Electromagnetic Fields?

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Homework Help Overview

The discussion revolves around the invariance of the expression E^2 - B^2 in electromagnetic fields and its relation to certain transformation groups. Participants explore the mathematical properties of specific matrices and their implications in the context of group theory.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the preservation of E^2 - B^2 under matrix transformations and question the identification of the corresponding group. There is an exploration of the relationship to the Lorentz group and the properties of matrices with complex entries.

Discussion Status

The conversation has led to the identification of the group SU(1,1) as relevant to the discussion. Some participants express uncertainty about the correctness of their calculations and the properties of specific matrices, indicating an ongoing exploration of the topic.

Contextual Notes

There is mention of potential errors in calculations and the informal nature of the discussion, with references to personal experiences affecting the reasoning process.

Mentz114
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I understand that [tex]E^2 - B^2[/tex] is invariant under various transformations.

If we consider the vector ( E, B ) as a column, then [tex]E^2 - B^2[/tex] is preserved after mutiplication by a matrix -

| cosh( v) i.sinh(v) |
| i.sinh(v) cosh(v) |

I think this transformation belongs to a group, but I can't put a name to it.
Does anyone recognise it ?

This matrix

1 i
i 1

also seems to preserve E^2-B^2 but is it a member of the preceeding ?
 
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If you look at what you are doing, this is the same as preserving the spacetime interval in 1+1 dimensions (t,x). So it's 'like' the lorentz group, though you've got complex entries and the one parameter family is not a group. Call it a subset of SU(1,1). The second matrix doesn't even preserve E^2-B^2.
 
Dick, thanks a lot.
I thought it might be a subset of 1+1 boosts.
I must have fumbled the calculation with the second matrix. Too much coffee...
 
Thanks again for naming the group. It is SU(1,1) in all its glory.
I had a lucky find which I've attached. It is a great intro to the group, see
especially section 6.1. I just noticed that the file is called SU12, that is an error,
it really is about SU(1,1).

M
 

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