The limit of ln(x^2 - 9) as x approaches 3 from the right is negative infinity. This occurs because as x approaches 3, the expression x^2 - 9 approaches 0, leading to the logarithm of a negative number, which is undefined. The key to understanding this limit lies in recognizing that ln(ab) = ln(a) + ln(b) can be applied, and that x^2 - 9 can be factored into (x - 3)(x + 3). Thus, the limit diverges to negative infinity as x approaches 3 from the right.
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JFerra said:Determine the infinite limit:
lim ln (x^2 - 9)
x -> 3^+
Don't understand how the answer is negative infinity.
Thanks for the help