What Happens to the Current Through R1 When E2 is Short Circuited?

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Homework Help Overview

The discussion revolves around a circuit involving two cells with emfs E1 and E2, and two resistors R1 and R2. The original poster is trying to understand the effect on the current through R1 when E2 is short-circuited.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply Kirchhoff's Voltage Law (KVL) to analyze the circuit before and after short-circuiting E2. They express confusion regarding the implications of short-circuiting E2 and how it affects the current through R1.
  • Some participants clarify the definition of short-circuiting a battery and discuss the resulting current flow, while others confirm the original poster's understanding of the current through R1 when R2 has no current flowing through it.
  • There are additional queries about the concept of short-circuiting a resistor, indicating a need for further clarification on the topic.

Discussion Status

The discussion is active, with participants providing clarifications about the implications of short-circuiting components in the circuit. There is a recognition of differing interpretations regarding the current through R1, but no explicit consensus has been reached.

Contextual Notes

Participants are navigating the definitions and implications of short-circuiting both batteries and resistors, which may influence their understanding of the circuit behavior. The original poster's confusion about the current calculations suggests a need for deeper exploration of the circuit's setup and assumptions.

subhradeep mahata
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Homework Statement


upload_2018-12-21_9-48-40.png

The above circuit shows two cells of emfs E1 and E2 and two resistors with resistances R1 and R2. If E2 is short circuited, then what is the current through R1?

Homework Equations

The Attempt at a Solution


First of all, i am not sure what it exactly means when a cell is short circuited, but i suppose it means no current flows through E2. Going by this notion, first we consider the case where nothing is short circuited and everything is normal. Then, i will apply KVL in three loops as:
upload_2018-12-21_9-55-53.png

In outer loop clockwise:
E1-R1i+E2=0
or, E1+E2=R1i .....(1)
Inner left loop clockwise:
E1-R1i-R2i1=0
or, E1=R1i+R2i1 .....(2)
Inner right loop clockwise:
E2+R2i1=0
or, E2=-i1R2 ......(3)

Now, from (3): i1= -E2/R2 ...(4)
from (1): i=(E1+E2)/R1 ...(5)
So, i-i1= {R2(E1+E2)}/R1R2 (Lets call this x)
The final circuit looks something like this:
upload_2018-12-21_10-12-9.png

Now, according to question, x=0.
So, on solving, we get E1+E2=-E2R1/R2
Substituting this in (5), we get i= -E2/R2
That's my final answer, but my books says the correct answer is E1/R1
Also, my teacher said that since no current flows through E2, the circuit has only E1, R1 and R2. So, required current= E1/R1+R2

I am terribly confused, Please help me out.
 

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Short circuiting the battery means that its terminals are connected with a wire of zero resistance, as shown in the figure by the red line. There flows a big current through the battery, and the voltage is zero across the terminals.

upload_2018-12-21_6-36-30.png
 

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@ehild and @haruspex
upload_2018-12-21_6-36-30-png.png

So no current is flowing through R2. Therefore, required current is E1/R1, right?
 

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Just one more query: when i say a resistor is short circuited, does that mean there is a zero resistor wire is connected across its ends as well?
 
subhradeep mahata said:
Just one more query: when i say a resistor is short circuited, does that mean there is a zero resistor wire is connected across its ends as well?
Yes.
 
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Okay, thanks.
 

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