What happens to the temperature of an object in vacuum?

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Discussion Overview

The discussion centers on the effects of placing an object, specifically a rock, in a vacuum within a steel container. Participants explore the implications for the rock's temperature as air is removed from the box, considering thermal energy transfer and the role of thermal radiation.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that the rock's temperature will equalize with that of the steel container, indicating that energy transfer occurs through thermal radiation.
  • Another participant questions whether the temperature of the rock drops when air is removed, drawing a parallel to the warming effect of compressed air.
  • A different viewpoint acknowledges that the rock will cool during the air removal process but asserts that this cooling is temporary and that thermal radiation will eventually equalize the temperatures.
  • It is proposed that if the mass of the rock is significantly greater than that of the air, the rock will experience minimal cooling from the air, especially if the air is removed rapidly.

Areas of Agreement / Disagreement

Participants express differing views on the immediate effects of air removal on the rock's temperature, with some asserting it cools temporarily while others emphasize eventual thermal equalization. No consensus is reached regarding the overall impact on the rock's temperature.

Contextual Notes

Participants discuss the assumptions regarding the rates of thermal energy transfer and the conditions under which the air is removed, which may affect the outcomes described.

petterg
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Hi guys.

I was wondering, what happens to the temperature of a object if it's put into vacuum?

Say you have a box of steal (something that transfers thermal energy fast between the inside and outside).
Inside the box you have a rock. The rock is held in the center of the box using something that does not transfer any kind of thermal energy.

Outside the box there is air with constant temperature.
The box itself has the same temperature as the air outside.
The rock and the air inside the box also has the same temperature.

Now you suck the air out of the box, so the rock is left in vacuum. What will happen to the temperature of the rock?
 
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Thank you for the reply.

If I get you right the temperature doesn't drop when the air is sucked out?

When air is compressed it's getting warmer. I would expect the opposite to happen when air is sucked out, and this would make the rock colder.
 
It will cool while you are pumping the air out, yes. As the pressure drops, the gas in the box will, indeed, cool down and cool the rock. But this will be temporary. Once you've reached sufficient vacuum and stopped pumping, temperature between the rock and the walls will equalize due to thermal radiation.
 
Ah. I see.
Thank you
 
K^2 said:
It will cool while you are pumping the air out, yes. As the pressure drops, the gas in the box will, indeed, cool down and cool the rock. But this will be temporary. Once you've reached sufficient vacuum and stopped pumping, temperature between the rock and the walls will equalize due to thermal radiation.

And, if the mass of the rock is much greater than the mass of the original air, the rock will experience very little cooling by the air. If the air were somehow removed instantaneously (or at least very rapidly), the rock temperature would virtually not change at all.
 

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