What Happens When the Ladder Operator Hits the Identity Operator?

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Homework Help Overview

The discussion revolves around the behavior of the ladder operator when it interacts with the identity operator in the context of quantum mechanics or operator algebra.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the identity operator, questioning the value of the commutator [A,1] and whether it simplifies to zero. There is also a discussion about the interpretation of the term "1" in this context.

Discussion Status

Some participants have provided insights regarding the identity operator and its properties, while others express confusion about the notation and its implications. There appears to be a mix of interpretations being explored without a clear consensus.

Contextual Notes

Participants note the potential for misunderstanding due to the notation used, particularly regarding the term "1" and its relation to the identity operator.

binbagsss
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Homework Statement
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Relevant Equations
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I'm just trying to follow the below
expop.png

And I understand all, I think, except what's happened to the term when A hits 1: [A,1] ?
If I'm correct basically we're just hitting on the first operator so reducing the power by one each time of the operator in the right hand bracket

thanks
 
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If I understand this correctly, ##1## is the identity operator. So what would be the value of ##[A,1]##?
 
[A,1]=0 since 1 is pure number!
 
Abhishek11235 said:
[A,1]=0 since 1 is pure number!
omg i think i need some sleeep ! thank you haha :)
 
binbagsss said:
omg i think i need some sleeep ! thank you haha :)
A typo! 1 here refers to identity operator as @tnich says. Anyways,final result is same
 

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