What Does Derivation Mean in a General Relativity Context?

  • Thread starter Thread starter bmb2009
  • Start date Start date
  • Tags Tags
    Derivation
Click For Summary
The discussion centers on the confusion regarding a homework assignment in a general relativity course, specifically about deriving the change in a vector under parallel transport. The professor's lecture notes contain an equation that appears to be a complete derivation, leading to uncertainty about whether students should rewrite the existing steps or provide additional commentary for clarity. Participants suggest that the professor may expect a more detailed explanation of the derivation process, as lecture notes often lack comprehensive detail. The original poster expresses frustration at not receiving a response from the professor for clarification. Overall, the conversation highlights the challenges of understanding expectations in academic assignments.
bmb2009
Messages
89
Reaction score
0

Homework Statement



This seems like a simple question but I've never asked it and I'm stuck haha
For my general relativity course we are asked to derive the change in a vector under parallel transport. My professor references his lecture notes on his course web page in the statement of the problem...he says "In the notes, derive all the steps in eq. 1.8"

But in the lecture notes the equation 1.8 seems to be the derivation itself. I.e. he has several steps of tensor analysis and arrives at the conclusion and says the final answer, that a vector does not change under parallel transport. This is what I would have considered a derivation.

Do you think he wants to re-write the steps already laid out for us and maybe write some side comments to show we understand what's going on in each step? Or is a derivation something else entirely?

and yes I did try to ask him about this but no luck on an email response. thanks!



Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Are there lots of steps missing in the notes? Maybe he just wants you to fill in all the gaps needed to get to this eq. 1.8. Usually lecture notes only have really brief and sketchy ("hand-waving") derivations of things, so he probably just wants you to do it more thoroughly.
 
kurros said:
Are there lots of steps missing in the notes? Maybe he just wants you to fill in all the gaps needed to get to this eq. 1.8.

That's what I thought... but the equalities and substitutions to derive further results are very well laid out and "easy" to follow. (easy meaning comprehensive)
 
Well, then I'm out of ideas :p.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
3
Views
4K
  • · Replies 53 ·
2
Replies
53
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 50 ·
2
Replies
50
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
1
Views
1K
  • · Replies 36 ·
2
Replies
36
Views
1K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 1 ·
Replies
1
Views
1K