What is an accumulation point?

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An accumulation point of a set S in R is defined as a point x where every deleted neighborhood around x contains at least one point from S. For the interval [0,1), points like 0, 0.5, and 1 are accumulation points because neighborhoods around these points intersect with S. Points outside this interval, such as those less than 0, are not accumulation points since their neighborhoods do not intersect S. Additionally, if x is an accumulation point, there exists a sequence in S that converges to x, indicating that accumulation points are closely related to the set. Understanding these concepts clarifies the nature of accumulation points in mathematical analysis.
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I don't know what an accumulation point is and I have read the definition many many times.

Could someone please give me a few examples with intervals of what would be an accumulation point?

Thank you!
 
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Fire flame said:
I don't know what an accumulation point is and I have read the definition many many times.

Could someone please give me a few examples with intervals of what would be an accumulation point?

Thank you!
Hello Fire flame. Welcome to PF !

What is the definition that you're trying to use, but don't understand?
 
Definition:

Let S be a subset of R. A point x in R is an accumulation point of S if every deleted neighborhood of x contains a point of S.

So this is what I get out of it.

Lets say S is a subset of R and S is the interval [0,1)

So basically, you take a point, any point x in R and then deleted that point and look at the neighborhood around that point, if you get something in S in YES that point is an accumulation point.

So from our interval [0,1)

0 is an accumulation point since in the neighborhood to the right side of zero there is something in S
1/2 or 0.5 is an accumulation point because on both sides of 0.5 there is a neighborhood that contains S
1 is an accumulation point since to the left of 1 there is a neighborhood that contains S

So is this the right way to thinking about accumulation points?

Thanks.
 
Fire flame said:
Definition:

Let S be a subset of R. A point x in R is an accumulation point of S if every deleted neighborhood of x contains a point of S.

So this is what I get out of it.

Lets say S is a subset of R and S is the interval [0,1)

So basically, you take a point, any point x in R and then deleted that point and look at the neighborhood around that point, if you get something in S in YES that point is an accumulation point.

So from our interval [0,1)

0 is an accumulation point since in the neighborhood to the right side of zero there is something in S
1/2 or 0.5 is an accumulation point because on both sides of 0.5 there is a neighborhood that contains S
1 is an accumulation point since to the left of 1 there is a neighborhood that contains S

So is this the right way to thinking about accumulation points?

Thanks.
That's a good start.

For your example in which set S is the interval [0,1), every point in S is an accumulation point.

Any point, a, to the left of 0 is not an accumulation point, because we can find a deleted neighborhood of a which doesn't intersect set S. such a deleted neighborhood is, (2a, a)∪(a, a/2) .

1 is an accumulation point because every neighborhood immediately to the left of 1 intersects set S.
 
Also interesting is that if x is an accumulation point of S, there's a sequence in S that converges to x. There's no "gap" between the accumulation point and the set; it's as close to the set as any point can get.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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