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I have in my problem, a ball sitting on a cylindrical rod that pivots at the bottom,
some guy in the explanation said parallel axis theorem and came up with moment of inertia of:
I = (mL^2)/3 + [2Mr^2/5 + M(L+r)^2]
where L is the length of the rod, m is the mass of the rod, M is the mass of the ball, r is the radius of the ball.
some guy in the explanation said parallel axis theorem and came up with moment of inertia of:
I = (mL^2)/3 + [2Mr^2/5 + M(L+r)^2]
where L is the length of the rod, m is the mass of the rod, M is the mass of the ball, r is the radius of the ball.