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Introductory Physics Homework Help
What is its linear speed at the bottom of the incline?
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[QUOTE="jimmyboykun, post: 4582061, member: 490778"] [h2]Homework Statement [/h2] A spherical object with a moment of inertia of 0.584mr2 starts from rest rolling down a 2.25-m high incline. If the sphere is rolling without slipping [h2]Homework Equations[/h2] I the best equation to use for this problem is k(initial)+u(initial)=k(final)+u(final) [h2]The Attempt at a Solution[/h2] I stretch the equation 1/2mv^2(initial)+1/2Iω^(initial)+mgh(initial)=1/2mv^2(final)+1/2Iω^2(final)+mgh(final). since the object started from rest the initial kinetic energy and the final potential energy is zero, which leads me to this equation mgh(initial)=1/2mv^2(final)+1/20.584mr^2ω^2(final). As I continue reduce the equations I round up with this. gh(initial)=0.792v^2(final) v=sqrt(9.81m/s^2)(2.25m)/0.792 the linear speed I came up with was 5.279m/s. Did I do this right? [/QUOTE]
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Introductory Physics Homework Help
What is its linear speed at the bottom of the incline?
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