What is result of this summation:sum(k=1, to n) sin(n*pi/k)I

  • Thread starter Emilijo
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In summary, the result of the summation is dependent on the specific values of n and k. The use of complex numbers, Euler's formula, and the sum of a geometric series can be helpful in solving this problem.
  • #1
Emilijo
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What is result of this summation:

sum(k=1, to n) sin(n*pi/k)

I put it in wolfram alpha but it doesn't give me the solution.
Where is the problem?
 
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  • #2
try using sinθ = Im(e) :wink:
 
  • #3


tiny-tim said:
try using sinθ = Im(e) :wink:

No, still doesn't calculate it.
 
  • #4


Emilijo said:
What is result of this summation:

[tex] \sum_{k=1}^n \sin(n \pi / k) [/tex]

I put it in wolfram alpha but it doesn't give me the solution.
Where is the problem?

tiny-tim said:
try using sinθ = Im(e) :wink:

Emilijo said:
No, still doesn't calculate it.

first of all, are you sure it isn't

[tex] \sum_{k=1}^n \sin(k \pi / n) [/tex]

instead?

second, in any case, complex numbers and variables, Euler's formula, and the sum of a geometric series are three mathematical methods that are your friends.
 

What is the result of this summation: sum(k=1, to n) sin(n*pi/k)?

The result of this summation is 0.

How do you calculate the summation sum(k=1, to n) sin(n*pi/k)?

The summation can be calculated by plugging in values for k starting at 1 and going up to n, and then adding all the resulting values together.

What is the significance of the variable n in this summation?

The variable n represents the number of terms in the summation. It determines how many times the function is evaluated and added together.

Can the result of this summation be negative?

No, the result of this summation is always 0. This is because the sine function is an odd function, meaning that sin(-x) = -sin(x). When evaluating the summation, each term will have a corresponding negative term that cancels it out, resulting in a total of 0.

Is there a simplified formula for calculating this summation?

Yes, there is a simplified formula for this summation: n/2. This can be derived using mathematical techniques such as the Fourier series and complex numbers.

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