What is the acceleration of a hockey puck sliding on a frozen lake?

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SUMMARY

A hockey puck sliding on a frozen lake comes to rest after traveling 175 meters with an initial velocity of 1.9 m/s. The correct acceleration, calculated using the kinematic equation \( a = \frac{\Delta v}{\Delta t} \), is -0.002857142 m/s². The time taken for the puck to stop is approximately 350 seconds. The discussion emphasizes the importance of understanding the definitions of acceleration and the correct application of kinematic equations.

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  • #31
JassC said:
A hockey puck sliding on a frozen lake comes to rest after traveling 175m.
If it's initial velocity is 1.0m/s, what is its acceleration if that acceleration is assumed constatnt?
Answer in units of m/s^2

I first divided 175/1.9 to get 92.11s. I then put 1.9/92.11 to get 0.02063. But it's wrong.

hi,if body moves linear then 2(acceleration)(distance)=(final velocity)^2 - (initial velocity)^2 fomulae can work. so d=175m and intial velocity=1.0m/s^2 and final velocity=0m/s^2
 

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