What is the Acceleration of a Small Body Moving on a Parabola?

  • Thread starter Thread starter GregoryGr
  • Start date Start date
  • Tags Tags
    Acceleration
Click For Summary
SUMMARY

The discussion focuses on determining the acceleration of a small body moving along the parabola defined by the equation y = ax², specifically at the point where x = 0. The key conclusion is that while the body maintains a constant speed, the acceleration is not zero due to the change in direction of the velocity vector. The acceleration is orthogonal to the velocity, and its magnitude can be derived by differentiating the position equations with respect to time.

PREREQUISITES
  • Understanding of vector differentiation
  • Knowledge of kinematic equations
  • Familiarity with parabolic motion
  • Basic concepts of acceleration and velocity
NEXT STEPS
  • Study vector calculus to improve differentiation skills
  • Learn about kinematic equations in two dimensions
  • Explore the properties of parabolic motion in physics
  • Investigate the relationship between velocity and acceleration in curved paths
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking to enhance their understanding of vector differentiation and parabolic trajectories.

GregoryGr
Messages
41
Reaction score
0

Homework Statement



a small body is moving in the plane xy with a constant (in size) velocity [ sorry for my english]. Find the acceleration for x=0 for the parabola [tex]y=ax^2[/tex]

Homework Equations





The Attempt at a Solution



[tex]v^2= a_x^2 +a_y^2 \\ \vec{v}= a_x\vec{x}+ a_y*\vec{y}[/tex] and $$\vec{a}=d\vec{v}/dt$$

I'm kind of lost now, mainly because I'm new to differentiating vectors... Any help would be helpful...
 
Physics news on Phys.org
Constant velocity means that acceleration is 0 or that the direction of velocity is changing, so is the velocity changing direction?
 
The magnitude of the velocity is usually called the speed. If the speed is constant then any acceleration is orthogonal to the velocity. So what direction will the acceleration be in at x=0?
It remains to determine the magnitude of the acceleration. By differentiating the equations you have you should be able to determine ##\ddot x^2+ \ddot y^2## as a function of x and the speed.
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
16
Views
1K