What Is the Actual Bond Angle in SeCl2 According to VSEPR Theory?

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SUMMARY

The actual bond angle in selenium dichloride (SeCl2) according to VSEPR theory is less than 109°, primarily due to the presence of lone pairs on the selenium atom. The Lewis structure indicates that SeCl2 has a bent molecular geometry, which reduces the ideal tetrahedral angle of 109.5° by approximately 2° to 4° for each lone pair present. Therefore, the correct answer to the bond angle prediction is option D, which states the angle is less than 109°.

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Homework Statement


Predict the actual bond angle in SeCl2 using the VSEPR theory.
a. more than 120°
b. between 109° and 120°
c. between 90° and 109°
d. less than 109°


Homework Equations





The Attempt at a Solution


So I tried to draw the Lewis Structure of the chemical and then the model of it. I also know that lone pairs made the bond angle smaller by about 2°.

I hope that this is the right structure:
[PLAIN]http://img101.imageshack.us/img101/7538/pretest4num4.png

Since the bond angle of a tetrahedral molecule is 109.5°, I would think that it lowered bond angles would be around 90° to 109°.

Any help is appreciated.
 
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Any help? Please and thanks.
 
I hate to answer when I am only partially sure. Intuition tells me you are OK.
 
Thanks for the help Borek :D
 
yes you are correct. the lone pairs reduce the tetrahedral ideal angle of 109.5o between atoms by about two or four degrees, depending on the individual atoms bonded together. So generally you are correct to assume that D is right.
 

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