What is the adjoint linear operator and how do you find it?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
terryaki1016
Messages
2
Reaction score
0
If L is the following first-order linear differential operator
L = p(x) d/dx
then determine the adjoint operator L* such that
integral from (a to b) [uL*(v) − vL(u)] dx = B(x) |from b to a|
What is B(x)?

sorry.. on my book there's only self-adjointness

i don't quiet understand what is the adjoint liear operator.

may someone solve this problem and tell me what exactly adjoint linear operator is ?
 
Physics news on Phys.org
The adjoint [itex]A^\dagger[/itex] of a linear operator [itex]A[/itex] is defined by [itex]\langle x,Ay\rangle=\langle A^\dagger x,y\rangle[/itex]. Physicists write the adjoint as [itex]A^\dagger[/itex], mathematicians write it as [itex]A^*[/itex]. A is self-adjoint if [itex]A^\dagger=A[/itex].
 
Fredrik said:
The adjoint [itex]A^\dagger[/itex] of a linear operator [itex]A[/itex] is defined by [itex]\langle x,Ay\rangle=\langle A^\dagger x,y\rangle[/itex]. Physicists write the adjoint as [itex]A^\dagger[/itex], mathematicians write it as [itex]A^*[/itex]. A is self-adjoint if [itex]A^\dagger=A[/itex].

how to find the A* then.. sry :(