What is the adjoint linear operator and how do you find it?

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SUMMARY

The adjoint linear operator, denoted as L*, is derived from the first-order linear differential operator L = p(x) d/dx. The relationship defining the adjoint is given by the integral equation integral from (a to b) [uL*(v) − vL(u)] dx = B(x) |from b to a|. The adjoint operator is crucial in understanding self-adjointness, where A* = A for the operator A. The discussion clarifies that physicists use A^† while mathematicians prefer A* to denote the adjoint operator.

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terryaki1016
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If L is the following first-order linear differential operator
L = p(x) d/dx
then determine the adjoint operator L* such that
integral from (a to b) [uL*(v) − vL(u)] dx = B(x) |from b to a|
What is B(x)?

sorry.. on my book there's only self-adjointness

i don't quiet understand what is the adjoint liear operator.

may someone solve this problem and tell me what exactly adjoint linear operator is ?
 
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The adjoint [itex]A^\dagger[/itex] of a linear operator [itex]A[/itex] is defined by [itex]\langle x,Ay\rangle=\langle A^\dagger x,y\rangle[/itex]. Physicists write the adjoint as [itex]A^\dagger[/itex], mathematicians write it as [itex]A^*[/itex]. A is self-adjoint if [itex]A^\dagger=A[/itex].
 
Fredrik said:
The adjoint [itex]A^\dagger[/itex] of a linear operator [itex]A[/itex] is defined by [itex]\langle x,Ay\rangle=\langle A^\dagger x,y\rangle[/itex]. Physicists write the adjoint as [itex]A^\dagger[/itex], mathematicians write it as [itex]A^*[/itex]. A is self-adjoint if [itex]A^\dagger=A[/itex].

how to find the A* then.. sry :(
 

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