What is the Angle Between the Target and Incident Ball Post-Collision?

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SUMMARY

The discussion focuses on a perfectly elastic collision involving two identical steel marbles, each weighing 45 g. After the oblique collision, the incident marble continues at an angle of 55 degrees to its original direction. To determine the angle between the target ball's direction and the incident ball's original direction, one must apply the principles of conservation of momentum and conservation of kinetic energy, rather than assuming the angle is simply 55 degrees.

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Fusilli_Jerry89
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Homework Statement


A 45 g steel marble collides obliquely w/ an identical stationary marble, and continues at 55 degrees to its original direction. The collision is perfectly elastic. What is the angle between the direction taken by the target ball and the original direction of the incident ball?

The Attempt at a Solution


is it just 55 degrees?
 
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Fusilli_Jerry89 said:

Homework Statement


A 45 g steel marble collides obliquely w/ an identical stationary marble, and continues at 55 degrees to its original direction. The collision is perfectly elastic. What is the angle between the direction taken by the target ball and the original direction of the incident ball?

The Attempt at a Solution


is it just 55 degrees?

It is not 55 degrees. You need to apply conservation of momentum and conservation of energy (kinetic energy in this case) to find the magnitude and direction of the velocity of the target ball.
 

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