What Is the Angle Between Velocity Vector and Trajectory at Maximum Height?

[Objection]

Homework Statement

the initial velocity of a projectile is 150 m\s .the angle between the velocity vector and the trajectory at the projectile's maximum height is
a) 90
b) 45
c) zero
d) 63.1
e) 36.9

Homework Equations

Vox= vx = Vocosθ
Vy = Vosinθ-gt
Range (R) = (vo)^2*sin(2θ)/g
Maximum Height (H) = (vo)^2*(sinθ)^2/2g

The Attempt at a Solution

http://im40.gulfup.com/43qMA.jpg

in this image we can see that the angle at the maximum height is 0 but I want to get sure ?

 

[CWatters]

Correct.