MHB What is the angular velocity of a hinged pole as a truck accelerates?

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To calculate the angular velocity of a hinged pole as a truck accelerates, the pole is released from a vertical position while the truck accelerates at 0.90 m/s². The uniform pole measures 3.6 m in length. The key equations involve relating linear and angular motion, specifically using the relationships between linear velocity, angular velocity, and acceleration. The challenge lies in incorporating the truck's constant acceleration into the equations governing the pole's motion. A correct approach will yield the angular velocity when the pole reaches the horizontal position.
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The uniform 3.6 m pole is hinged to the truck bed and released from the vertical position as the truck starts from rest with an acceleration of 0.90 m/s2. If the acceleration remains constant during the motion of the pole, calculate the angular velocity of the pole as it reaches the horizontal position.

I believe I know this question however I wanted to be sure
 
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Please go ahead and post your solution so far, then.
 
Never mind my solution was wrong although I think that using the equations

Vr=0
Vtheta=r*Theta
Ar=-r*Theta(dot)^2
Atheta=r*Theta(double dot)

However i am unsure as to how to add the trucks acceleration into the solution.
 
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