What is the Approximation for Retarded Time?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 3K views
noamriemer
Messages
50
Reaction score
0
Hello again!
Facing some problems (my exam is taking place tomorrow... help is needed. Many thanks in advance!)

I need to find an approximation for a retarded time. I don't understand how. This is what my lecturer wrote: [itex]sin(\varphi-\omega t)=exp(i\varphi'-i\omega(t-r/c)-i\omega(r'cos\theta cos\theta'+r'sin\theta sin\theta'cos(\varphi-\varphi'))/c[/itex]


Could you please explain how ?
Thank you!
 
Physics news on Phys.org
I think you copy incorrect. You are assuming harmonic wave in you case where it is a sinusoidal wave. Usually it is represented by cosine wave:

[tex]cos ( \beta z -\omega t -\phi) = cos ( \omega t -\beta z +\phi) = \Re e[e^{j\omega t}e^{-j\beta z}e^{j\phi}][/tex]

The way you look at this is the peak of the cosine function is at [itex]\omega t - \beta z +\phi = 0[/itex]. Let's first assume [itex]\phi= 0[/itex] to simplify the problem. So if z is positive, then t has to be positive to get [itex]\omega t - \beta z = 0[/itex]. In words, if you start at z=0, it takes [itex]\omega t = \beta z[/itex] for the wave at z=0 to reach z. So this is the retard time function.