What is the average acceleration of a solid sphere rolling down an incline?

[alex_boothby]

would

(5/7) gsinΘ (the symbol is a theta)

give me the average acceleration of a solid sphere rolling down an incline, I am not also sure where the 5/7 came from, I've herd of 2/5 for inertia but... AND is that linear acceleration or rotational.

that equation give about 0.6

i also get about 0.6 when i calculate the acceleration from my data by 2s/t^2 which is from s=ut+ 1/2 at^2


im also confused to why when i do v(final) - v (intial) / time
i do not get 0.6 well i do for the first value, then for the other distance i do not!
and ages ago i got 0.3 but now i can't even remember were that came from, i do get 0.3 if i do that eqaution for average v, but once again only for the first value.

thanks for any help, i think i just need reasuring that i am doing it right, as i have got .6 from to different things.

 

[vaishakh]

Under no friction condition the particle will simply slide. You have mentioned nothing about friction here.

 

[alex_boothby]

thats hasnt yet come into it yet, i want to verify that the above calculations are correct first

 

[vaishakh]

Sorry - its given to be rolling in the question.
Well the force on the body is mgsin(theta) and that should be the acceleration.

 

[Doc Al]

would

(5/7) gsinΘ (the symbol is a theta)

give me the average acceleration of a solid sphere rolling down an incline, I am not also sure where the 5/7 came from, I've herd of 2/5 for inertia but... AND is that linear acceleration or rotational.

Don't just use some equation at random that you plucked from a book. Especially if you don't know know what it's supposed to be for.

That equation is correct (for a solid sphere rolling without slipping down a flat incline), but derive it yourself using Newton's 2nd law if you plan on using it. (You should be able to tell whether it's linear or angular acceleration by just looking at the units.)

 

[alex_boothby]

well thers no inertia so i assume its linear, i tried to derive it from Newton second law, but got awfuly baffeled and decided long as it works nicely!