What is the average air resistance for a person?

Click For Summary
SUMMARY

The average air resistance for a person can be estimated using the drag equation, specifically D = C_d * (ρ * V² * A) / 2, where D is the drag force, C_d is the drag coefficient (approximately 0.7 for a human), ρ is the air density, V is the velocity, and A is the cross-sectional area (1.60 m² for an average-sized person weighing 70 kg). At terminal velocity, the drag force equals the weight of the person, leading to the equation mg = C_d * (ρ * V² * A) / 2. This relationship allows for the calculation of terminal velocity based on the aforementioned parameters.

PREREQUISITES
  • Understanding of the drag equation and its components
  • Knowledge of basic physics concepts such as force and terminal velocity
  • Familiarity with the concept of drag coefficient
  • Basic mathematical skills for rearranging equations
NEXT STEPS
  • Research "air density variations with altitude" to understand its impact on drag
  • Learn about "terminal velocity calculations" for different body shapes and sizes
  • Explore "fluid dynamics principles" related to drag forces
  • Investigate "real-world applications of drag coefficients" in sports and engineering
USEFUL FOR

Physics students, engineers, and anyone interested in understanding the dynamics of falling objects and air resistance calculations.

Br0kenS0cial
Messages
7
Reaction score
0
I can't seem to come up with a decent formula/accepted value for air resistance.

I realize there are things that need to be taken into account, but I am already delving into things way beyond what I've done per the course work, and I don't want to bite off more than I can chew. I understand there is no exact formula for air resistance, but I need a number to find a terminal velocity.

Can anybody give me a ball park figure for an averaged sized person? (m=70kg, A=1.60m)
 
Physics news on Phys.org
Last edited by a moderator:
Oh, right. I forgot to include that I was using a value of 0.7 for my drag coefficient. Sorry.
 
Er. Thanks for the help, you two, but I really haven't got an answer for this.

Is there one?
 
Well what happens at terminal velocity? It means that the velocity doesn't increase, othewise it wouldn't be terminal velocity. If velocity doesn't increase, there is no acceleration, and that means that the net force of the falling object is zero, which means the Drag Force, D, must equal the weight of falling object.

So D = mg, and looking at the NASA site D\,=\,C_d\frac{\rho{V^2}A}{2},

where \rho is the density of air, V is the velocity of the object in the air, A is the cross-sectional area normal to the flow (or trajectory), and Cd is the drag coefficient.

So combining the two equations

mg\,=\,C_d\frac{\rho{V^2}A}{2}.

The rearrange terms and one gets V2 = . . . . . , and V = terminal velocity.
 
hahah that's just my problem, I'm looking for p.
 
Think of what happens to the equation in my link when t goes to infinity. And that equation will give you everything you need to find the terminal velocity.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
Replies
1
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
1
Views
2K
Replies
1
Views
3K
Replies
5
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
4
Views
8K
Replies
13
Views
3K