Concept: Air Resistance in Projectile Motion

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Homework Help Overview

The discussion revolves around the effect of air resistance on projectile motion, specifically focusing on a tennis ball launched at a 45-degree angle. The original poster, Sharna, seeks to understand why air resistance impacts the horizontal range more significantly than the maximum height of the ball.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Sharna attempts to connect theoretical concepts with practical observations, questioning the relationship between air resistance and projectile motion. Participants suggest considering the effects of speed on air resistance and friction, while also exploring the differences in average velocities in the horizontal and vertical directions.

Discussion Status

The discussion is ongoing, with participants providing hints and prompting further inquiry into the concepts of air resistance and velocity. There is an exploration of how these factors influence the horizontal and vertical components of projectile motion, but no consensus has been reached yet.

Contextual Notes

Sharna expresses confusion regarding the terminology in her notes, particularly the use of "Newtons" in the context of velocity, and is grappling with the implications of friction on the horizontal range versus vertical height.

ibwm
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Hi, I am in need for some physics help regarding the effect of air resistance on projectile motion.

My question is "For a tennis ball stuck at an angle of 45 degrees to the horizontal at typical speed without spin, why does air resistance have a greater effect on the horizontal range of the ball rather than the maximum height of the ball?"

I've tried searching Google for a solution, but have yet been able to find one. I don't just want to copy the answer off of the internet, but actually learn the concept.

Any help is much appreciated,
Sharna.

Edit:
In my notes I have:

For launch angle of 45 degrees, Vh and Vv = sin45 and cos45 = 0.707N (I have no idea why it says Newtons here if it's talking about velocity)

And then my notes say: "Theory: Vh= constant = x. Vv= x --> 0 --> x. Average Vh = x (more friction), Average Vv=x/2 (less friction)"

I am still unsure as to what all of this means. What is the reasoning behind the horizontal range being affected more by air resistance than the vertical height? Does it have something to do with friction forces being larger when velocity is larger?
 
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Here is a hint: in which case do you feel more wind? Driving at 10mph? Or driving at 60mph?
 
DaveC426913 said:
Here is a hint: in which case do you feel more wind? Driving at 10mph? Or driving at 60mph?

You'd feel more wind driving at 60mph, yeah? I know that there's more friction the faster you are travelling, but I am unsure as to how this affects horizontal distance more than vertical distance. What is the concept behind this?
 
ibwm said:
You'd feel more wind driving at 60mph, yeah? I know that there's more friction the faster you are travelling, but I am unsure as to how this affects horizontal distance more than vertical distance. What is the concept behind this?
What is the average velocity of the ball in the y direction as compared the average velocity of the ball in the x direction? They definitely be can't the same since at one point in its trajectory, y velocity is zero.
 
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