What Is the Average Force Produced by One Gallon of Gasoline?

Click For Summary
SUMMARY

The average force produced by one gallon of gasoline, which contains 3.1 x 107 calories of potential energy, can be calculated using the formula for work, where work equals force multiplied by distance. Given that one gallon of gasoline can move a car through a displacement of 25 miles, the calculation involves converting calories to Joules and miles to meters. The final result is an average force of approximately 3220.8 Newtons, confirming the efficiency of energy conversion from gasoline to mechanical work.

PREREQUISITES
  • Understanding of energy conversion (calories to Joules)
  • Familiarity with unit conversions (miles to meters)
  • Knowledge of the work-energy principle (work = force x distance)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of energy conversion efficiency in combustion engines
  • Learn about the relationship between force, work, and energy in physics
  • Explore advanced unit conversion techniques for various measurements
  • Investigate real-world applications of average force calculations in automotive engineering
USEFUL FOR

Students in physics or engineering, automotive engineers, and anyone interested in the mechanics of energy conversion in vehicles.

teremala
Messages
2
Reaction score
0

Homework Statement


"One gallon of gasoline contains 3.1*10^7 calories of potential energy that are released during combustion. If 1 gal of gasoline can provide the force that moves a car through a displacement of 25 mi, what is the average force produced by the gasoline?"

Homework Equations


This is where I am confused. All of the equations I can think of for average force require velocities, mass, time, etc. and I don't see how to get from here to there. Right now I am just using 1 cal = 4.18 Joules and 1 mi = 1609.3 m.

The Attempt at a Solution


Assuming complete efficiency,
3.1*10^7 cal / 25 mi = 1.24 * 10^6 cal / mi
then multiply that by 4.18 Joules/1 cal and by 1 mi/1609.3 m to get 3220.8 J/m (or N).

This could of course be multiplied back out to "work", but that strikes strikes me as circular. I just don't know if the answer I have is reasonable/what the question wants, since it's flagged as difficult and I haven't done anything but convert units. What am I missing?
 
Physics news on Phys.org
See what you can do with: work = force * distance.
 
Thanks, that was what the professor said too. As far as I can tell though work=f*d was already accounted for when I averaged calories/mile. In any case, this was the correct answer.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
3K
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K