What Is the Average Kinetic Energy of a Nitrogen Molecule at 25°C?

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SUMMARY

The average kinetic energy of a nitrogen molecule at 25°C is calculated using the formula KE = (5/2) kT, where k is the Boltzmann constant (1.38 x 10-23 J/K). The correct calculation yields an average kinetic energy of approximately 6.1686 x 10-21 J. This value is not listed among the provided answer choices, indicating that all options are incorrect. The discussion clarifies that nitrogen molecules, being diatomic, have rotational kinetic energy contributing to their overall kinetic energy.

PREREQUISITES
  • Understanding of kinetic energy equations in thermodynamics
  • Familiarity with the Boltzmann constant (k)
  • Basic knowledge of molecular structure and behavior
  • Ability to perform calculations involving temperature in Kelvin
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  • Study the derivation of the kinetic energy formula for diatomic molecules
  • Learn about the implications of rotational and vibrational energy in molecular physics
  • Explore the concept of temperature and its relation to kinetic energy
  • Investigate the role of the Boltzmann constant in statistical mechanics
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Students in physics or chemistry courses, educators teaching thermodynamics, and anyone interested in molecular behavior and kinetic theory.

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Homework Statement


The average kinetic energy of a nitrogen molecule at temperature 25c is _____ .

Select the correct answer.
1)5*10^(-21) J
2)3*10^(-20) J
3)1*10^(-20) J
4)9*10^(-20) J
5)8*10^(-21) J
(i guess they are all wrong )

Homework Equations


KE=3/2 K.T

The Attempt at a Solution



KE(av)=3/2 KT = 3/2 * 1.38*10^(-23) * (25+273)=6.1686*10^(-21) J

i just want to know whether my solution is correct or no ..
 
Physics news on Phys.org
A nitrogen molecule is not a single atom. It can rotate...
 
mfb said:
A nitrogen molecule is not a single atom. It can rotate...
got it thanks

K.E=5/2 KT
 

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