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mk9898
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Homework Statement
Die average kinetic energy and impuls squared of a single molecule are:
$$<E_{kin}>= 6.5*10^{-21} J$$ and $$<p^2> = 1.8*10^{-45} kg^2m^2s^{-2}$$
Which gas ist it?
3. The Attempt at a Solution
##\frac{m<v^2>}{2}=\frac{<p^2>}{2m}## ##\Leftrightarrow## ##\frac{<p^2>}{<v^2>} = m^2##
Therefore is ##m^2 = 2.77*10^{-25}kg ## and ##m = 5.26*10^{-13}kg##
I searched and attempted to find with gas it is based off of the mass and also multiplying it by a mole but to no avail.
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