What is the average pressure exerted on the other pedestal.

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Homework Help Overview

The problem involves calculating the average pressure exerted on a pedestal supporting a granite sculpture. The sculpture weighs 102 kg and is balanced on two pedestals with different contact areas. One pedestal has an area of 25 square centimeters and sustains an average pressure of 2 kg/square centimeter, while the other pedestal has an area of 13 square centimeters.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between force, area, and pressure using the formula p=F/A. There is an exploration of how the total weight of the sculpture affects the forces on each pedestal. Questions arise about the distribution of weight and whether the other pedestal must support the remaining weight after accounting for the first pedestal's contribution.

Discussion Status

Participants are actively engaging with the problem, attempting to calculate the pressure on the second pedestal based on the weight supported by the first. There is a recognition of the total weight that needs to be supported, and some participants are questioning their calculations and assumptions about the distribution of weight.

Contextual Notes

There is an emphasis on showing work and understanding the underlying principles rather than simply providing answers. Participants express uncertainty about their calculations and seek clarification on the correct approach to the problem.

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Homework Statement


An artist has designed a sculpture made from granite. The sculpture is essentially a small rectangular block whose weight is 102 kg. This centerpiece will be balanced on two granite pedestals, one at each end of the centerpiece. The pedestals are different sizes, such that one pedestal has a total area of contact with the centerpiece of 25 square centimeters and the other has an area of contact of 13 square centimeters. The first pedestal (area = 25 square centimeters) sustains an average pressure of 2kg/square centimeter. (Here "kg" means the force exerted by a mass of 1 kg.) What is the average pressure exerted on the other pedestal. Show Your Work!

Any help would be great. Thanks!



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The Attempt at a Solution

 
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lokal704 said:
Show Your Work!

Any help would be great. Thanks!

Actually any work shown would be great.

Thanks.
 


Oh, sorry. This is the second time I have used this forum, and I am still new.

Here is what I have so far:

p=F/A

First answer:

2=F/25
2*25=F
F=50

so would it be

p=50/13
p=3.85 kg?
 


lokal704 said:
Oh, sorry. This is the second time I have used this forum, and I am still new.

Here is what I have so far:

p=F/A

First answer:

2=F/25
2*25=F
F=50

so would it be

p=50/13
p=3.85 kg?

Almost. According to the statement you have 2 lbs over 25 cm2 and as you point out that represents 50 lbs overall.

But doesn't the object actually weigh 102 kg and hence doesn't the other pedestal need to provide for all of the remainder?
 


SO would it be the remaining 52 kg? Or 102 kg?
 


lokal704 said:
SO would it be the remaining 52 kg? Or 102 kg?

Well let's think about it.

If one end is holding up 50 kg, what will the other end hold up? What must the two ends support totally if it is at rest?
 


it would be 52 right? Because collectively they are supporting 102. So it should look like this right? Please correct me if I am wrong.

p=52/13

p=4kg
 

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