What is the Behavior of Solutions of a DE with Limits as t Approaches Infinity?

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SUMMARY

The general solution to the differential equation y' - 2y = 3e^t is y = -3e^t + ce^(2t). As t approaches infinity, the term ce^(2t) dominates due to its exponential growth compared to -3e^t. Therefore, if c is positive, the solution approaches positive infinity, while if c is negative, the solution approaches negative infinity. This confirms that all solutions will increase exponentially as t approaches infinity.

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Homework Statement



Find the general solution of the given differential equation, and use it to determine how
solutions behave as t→∞.

y' − 2y = 3et



Homework Equations



DE

The Attempt at a Solution



After some work, I got y=-3et+ce2t . Now I have problems in getting the limit as t goes to infinity. C can possibly be a positive or negative value. In case it is -ve, the answer goes to negative infinity. If it is positive, I can't really figure out what would the limit be. In the book however, it is written that 'It follows
that all solutions will increase exponentially'. HOW?
 
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e2t will beat et, so it will go to positive or negative infinity according to the sign of c.
 

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