fran1942 Messages 80 Reaction score 0 Thread starter Apr 14, 2011 #1 very sorry, this does not belong in this forum. Last edited: Apr 14, 2011
Fewmet Messages 406 Reaction score 38 Apr 14, 2011 #2 It's really just the two steps: factor (x-3) out of each term and then distribute to make 2(X+2) be 2x+4. Does that help?
It's really just the two steps: factor (x-3) out of each term and then distribute to make 2(X+2) be 2x+4. Does that help?