What is the bicycle speed after the throw?

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The discussion centers on calculating the bicycle speed after Tony throws his pack forward. The initial momentum of the system is 330 kg*m/s, which remains constant after the throw. The velocity of the pack relative to the ground is 6 m/s, combining the bicycle's speed and the pack's throw speed. The final momentum equation leads to the conclusion that the bicycle's speed after the throw is approximately 5.41 m/s. The problem is resolved successfully, confirming the calculations.
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Homework Statement



Tony of mass 55kg coasts on his bi cycle of mass 5 kg at a constant speed of 5m/s carrying a 6kg pack. tony throws his pack forward, in the direction of his motion, at 1 m/s relative to the speed of bicycle just before the throw.

Initial momentum of system (tony, bicycle, pack) is 330 kg* m/s
Momentum of system after pack is thrown is 330 kg*m/s

What is the bicycle speed after the throw? Answer in kg*m/s

Homework Equations





The Attempt at a Solution



330 / 5 = 66 kg*m/s

or 330 / 61 = 5.41 kg*m/s
 
Last edited by a moderator:
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Momentum of system after pack is thrown is 330 kg*m/s = (Mass of tony + Cycle)*v + Mass of the pack*its velocity. Velocity of pack with respect to the ground is 5 + 1 = 6m/s.
 
Thanks i got the answer!
 
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