What is the change in entropy of raspberry jelly during heating?

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SUMMARY

The discussion focuses on calculating the change in entropy of raspberry jelly during the heating process from 23.0°C to 220°F. The mixture consists of 952 g of raspberry juice and 930 g of sugar, with the specific heat of sucrose being 0.299 cal/g·°C. The energy absorbed by the mixture is calculated to be 4.19 x 10^5 J. To determine the change in entropy, the correct approach involves using the formula m*c*ln(Tf/Ti) for both components and summing the results.

PREREQUISITES
  • Understanding of thermodynamics, specifically the concepts of heat transfer and entropy.
  • Familiarity with specific heat capacity calculations.
  • Knowledge of logarithmic functions and their application in thermodynamic equations.
  • Basic principles of energy conservation in heating processes.
NEXT STEPS
  • Learn about the derivation and application of the entropy formula m*c*ln(Tf/Ti).
  • Study the principles of heat transfer in mixtures, particularly in food science.
  • Explore the specific heat capacities of various substances, including water and sucrose.
  • Investigate the relationship between energy absorbed and temperature change in thermodynamic systems.
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, food scientists involved in food processing, and anyone interested in the physical chemistry of cooking and heat transfer.

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Homework Statement


In making raspberry jelly, 952 g of raspberry juice is combined with 930 g of sugar. The mixture starts at room temperature, 23.0°C, and is slowly heated on a stove until it reaches 220°F. It is then poured into heated jars and allowed to cool. Assume that the juice has the same specific heat as water. The specific heat of sucrose is 0.299 cal/g·°C. Consider the heating process.

(b) How much energy does the mixture absorb?
(c) What is the minimum change in entropy of the jelly while it is heated?

The Attempt at a Solution



I have calculated part b, but I can't figure out how to do part c. For part b I got an answer of 4.19 x 10^5 J.

I just can't figure out what to do for part C. Since it absorbs 4.19 x 10^5 J I did Q/T, but that is wrong. Any help would be nice, thanks.
 
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Would I find the entropy by using m*c*ln(Tf/Ti) for both of the materials and then adding that together?
 
Anyone?
 

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