- #1

ymehuuh

- 19

- 0

## Homework Statement

An aluminum rod is 23.0 cm long at 20°C and has a mass of 350 g. If 12500 J of energy is added to the rod by heat, what is the change in length of the rod?

Answer is in mm

## Homework Equations

Q=m*c*delta T

deltaL=alpha*L0*deltaT

alpha=24x10^-6

c=900j/kg

## The Attempt at a Solution

12500=.35kg*900(Tf-20C)

Tf=59.68

deltaL=24x10^-6*.23m*39.68

The answer I get is 2.19*10-4m which is wrong

That /1000 to get mm is 2.19*10-7 which is wrong

I don't understand what I did wrong...