- #1
ymehuuh
- 19
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Homework Statement
An aluminum rod is 23.0 cm long at 20°C and has a mass of 350 g. If 12500 J of energy is added to the rod by heat, what is the change in length of the rod?
Answer is in mm
Homework Equations
Q=m*c*delta T
deltaL=alpha*L0*deltaT
alpha=24x10^-6
c=900j/kg
The Attempt at a Solution
12500=.35kg*900(Tf-20C)
Tf=59.68
deltaL=24x10^-6*.23m*39.68
The answer I get is 2.19*10-4m which is wrong
That /1000 to get mm is 2.19*10-7 which is wrong
I don't understand what I did wrong...