- #1

BunDa4Th

- 188

- 0

## Homework Statement

A steel ring with a hole having area of 3.96 cm2 is to be placed on an aluminum rod with cross-sectional area of 4.00 cm2. Both rod and ring are initially at a temperature of 36.0°C. At what common temperature can the steel ring be slipped onto one end of the aluminum rod?

## Homework Equations

DeltaA = yA_0DeltaT

T = T_0 + DeltaT

DeltaT = A_a - A_s/(y_sA_s) - (y_aA_a)

## The Attempt at a Solution

first i did 4 - 3.96 = .04 which is DeltaA

knowing that alluminum is 24x10^-6 (*C^-1) and steel is 11x10^-6 (*C^-1)

since the steel ring needs to be expand so it can fit in the alluminum rod i did

.04 = (11x10^-6)(3.96)(DeltaT) solve for DeltaT (i get this real huge number which is incorrect most likely)

T = T_0 + DeltaT when input its incorrect and when i try T = T_0 - DeltaT is also incorrect.

Last edited: