What is the charge on a circular segment of a wide charged electrode?

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Homework Help Overview

The problem involves calculating the charge on a circular segment of a wide charged electrode, given the electric field strength at a certain distance from the electrode. The subject area pertains to electrostatics and electric fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between electric field strength and charge density, referencing Gauss's Law. There are attempts to clarify the use of variables and equations related to charge density and area.

Discussion Status

The discussion is ongoing, with participants providing insights into the relevant equations and concepts. Some guidance has been offered regarding the interpretation of symbols and the calculation of charge density.

Contextual Notes

There is some confusion regarding the notation for charge density, with different symbols being used. Participants are also addressing the need to correctly calculate the area based on the diameter provided.

starrynight24
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Homework Statement



The electric field strength 5cm from a very wide charged electrode is 1000N/C. What is the charge (in nC) on a 1cm diameter circular segment of the electrode?

Homework Equations



E=Q/EoA

n=Q/A

3. The Attempt at a Solution [/b

I tried to figure out n, so that I can plug it into n=Q/A to figure out Q. But it didn't work.
 
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Since the electrode is so wide compared to how far away the electric field is measured at, we may treat the electrode as an infinite insulating plane of charge for which the electric field is given by Gauss's Law. It yields [tex]E\equiv\frac{\sigma}{\epsilon_0}[/tex] where [tex]\sigma[/tex] is the area charge density of the plate. This is essentially what you had. You're given the electric field. Just make sure that when you calculate the area that you use the radius since you are given the diameter.
 
What equation do I need to use to apply the area and the electric field to get the charge? n=Q/A?
 
I'm not sure what your n is supposed to be.. Apparently is the area charge density which is conventionally denoted as [tex]\sigma[/tex]. You are given the electric field so you can find the sigma and you also know the area so you can find the charge.
 
Two symbols are being used for charge density here:

n = Q/A

[tex]\sigma[/tex] = Q/A
 

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