What is the coefficient of friction for a given surface and two weights?

[SimonJ]

Homework Statement

I need to find the coefficient of friction on a surface. Two weights were given, 0.5672kg and 0.050kg

Homework Equations

m1a + Mm1g = m2g - m2a

The Attempt at a Solution

(0.5672kg)a + M (0.5672)(9.81) = (0.050kg)(9.81) - (0.050kg) a


M represents the coefficient of friction. I need to solve for that, I just don't know where to take it from here.

 

[mgb_phys]

That's not enough of a question - what were the two weights doing?

 

[SimonJ]

That is what is happening

 

[mgb_phys]

That helps.
Now try drawing in the forces.
The frictional force is = coeff_friction * normal force (ie weight)

 

[SimonJ]

Can you explain that a little more please?

 

[mgb_phys]

There is a force down on the 0.05kg mass = m g
This same force pulls the larger mass to the right, so an equal friction force acts to the left (assuming no loss in the pulleys).
The definition of coeeficient of friction is
friction force = coeef * normal force

The normal force is the force acting down on the suface = M g

 

[SimonJ]

Ok thanks!