What Is the Coefficient of Kinetic Friction in This Physics Problem?

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SUMMARY

The coefficient of kinetic friction for the given physics problem is calculated to be 0.2. This is derived from the equation for frictional force, where a forward horizontal force of 50N is applied to a crate weighing 250N, resulting in a constant velocity. The calculation confirms that the frictional force equals the applied force, leading to the conclusion that the coefficient is 0.2.

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Spartan Erik
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Homework Statement


"A forward horizontal force of 50N is used to pull a crate, which weighs 250N, at a constant velocity across a horizontal floor. The coefficient of kinetic friction is:"

Homework Equations


Frictional force = coefficient of kinetic friction x normal force

The Attempt at a Solution


This problem seems too easy, that's why I'm wondering if I might be wrong:

Frictional force = coefficient of kinetic friction x normal force
50N = coefficient x 250N
50N / 250N = coefficient
coefficient = 0.2

Is that all? Thanks
 
Physics news on Phys.org
yup that is correct.
 

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