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Static and Kinetic Friction problem

  1. Oct 21, 2012 #1
    1. The problem statement, all variables and given/known data[/b]
    A box weighing 100N is at rest on a horizontal surface. The coefficient of static friction between the box and the surface is 0.5, and the coefficient of kinetic friction is 0.25. If the crate is pushed with a force of 20N parallel to the floor, which of the following is true?

    2. Relevant equations[/b]
    Force of Friction=μ(normal force)

    3. The attempt at a solution[/b]
    The static friction force is μ(normal force) and normal F=100N. Static Ff=0.5(100N)=50N. And the box is pushed with less force than the max static Ff so "the crate will remain stationary, due to the static Ff of 50N which opposes the intended motion"... but I got it wrong. I don't know why. Help?
     
  2. jcsd
  3. Oct 21, 2012 #2
    What were the other answer options?
     
  4. Oct 21, 2012 #3
    The right answer choice was "the crate will accelerate across the floor at 3m/s^2." But at could be wrong because that was my friend's answer, and we might have different versions.
     
  5. Oct 21, 2012 #4

    Ibix

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    Science Advisor

    What would Newton say about a 50N force in one direction and a 20N force in the other?
     
  6. Oct 21, 2012 #5
    Ummm... the box would move to the direction of 50N force?
     
  7. Oct 21, 2012 #6
    So the box wouldn't move because 50N static Force of friction is greater than the 20N pushing force? That's what I put and I got the wrong answer. I mean, the static friction isn't causing the box to move in the other direction..
     
  8. Oct 21, 2012 #7
    Think about this suggestion, and draw a force diagram if it helps. What is the static friction force when the block is at rest?
    This is a little like if I told you that a force of 3000N is required to break down my front door. If it exerted 3000N whenever someone touched it, they would go flying backwards. This obviously isn't the case, and simply from F=ma we know that if we have a = 0, then F = Fn.
     
  9. Oct 21, 2012 #8
    So the static Ff is 50N at rest? Then what's the maximum static Ff? And even if the box moved, the kinetic friction force would be 25N which is still less than 20N so it can't accelerate (I think). Could somebody at least tell me if the "right answer" is correct? If it is, I still have to show work so I'm going to ask my teacher anyways, and if it' not, well then, I have to move on cause I have a lot to do.
     
  10. Oct 21, 2012 #9
    No, my point was that there is no "friction force" when we're not pushing on the box. There is always a static coefficient, but I was trying to get you to think of it like a wall that requires a certain force to break through. In my example, if I push on the door with 400 N, it pushes back with a normal force of 400 N, all the way up to 3000 N, at which point the net force becomes unbalanced and the door accelerates as it breaks.

    I believe your answer was correct, other than stating that Ff = 50N. Ff is in fact just equal and opposite to your applied force, up to 50 N, at which point it "breaks" and then kinetic friction takes over. So the answer should be something like, ""the crate will remain stationary, due to the static Ff of 20N which opposes the intended motion"

    Edit: Incase it wasn't clear, your friend must have a different version of the question.
     
  11. Oct 22, 2012 #10
    Yes, I got it now, that was exactly the answer. Thank you all, especially bossman27!
     
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