What is the Constant 'a' in the Initial Mass Function for a Globular Cluster?

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Homework Help Overview

The problem involves determining the constant 'a' in the initial mass function for a newly formed globular cluster, given its total mass and a specific mass function equation.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to find the number of stars within a specified mass range to apply the given mass function. There is a mention of uncertainty regarding the expected number of stars based on the mass range provided.

Discussion Status

Some participants have engaged in clarifying the original poster's approach, with one suggesting the integration of the mass function to find the number of stars. There is no explicit consensus on the method, but guidance has been offered regarding the integration process.

Contextual Notes

The original poster's inquiry appears to be influenced by previous discussions on the same topic, indicating a potential misunderstanding of forum rules regarding multiple threads for similar questions.

kranav
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Homework Statement



the question says, consider a newly formed globular cluster, with a total mass 10^6 times mass of the sun and an initial mass function dN/dm = a.m^-2.35 in the mass range 0.1 - 20 times mass of the sun, where m = M/mass of the sun.
find the constant a. (answer : 1.9 x10^5)
thanks.

Homework Equations





The Attempt at a Solution



the number of stars in a globular cluster are between 10^4 - 10^6. but N from the above equation should be smaller as the mass range is from 0.1 to 20 times sun's mass. If I can find that N the equation is a piece of cake.
 
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I'm really sorry about that ... wasn't aware of that. I thought if I could reframe the question and start afresh
 
After looking up "initial mass function", it looks like the number of stars in the mass range m_0 to m_1 is given by

N=\int_{m_0}^{m_1}\frac{dN}{dm}mdm

Have you tried performing this integration?
 
Yes this time I got it. Thank you very much
 

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