About initial mass function and mean mass in stellar cluster

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Homework Help Overview

The discussion revolves around calculating specific mass points in a stellar cluster using the Salpeter initial mass function (IMF). The problem involves determining the mass point at which half of the total mass and half of the total luminosity lies in more massive versus less massive stars, given certain mass limits.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the Salpeter IMF to find mass points related to mass and luminosity distributions. Some participants question the accuracy of the equations used, particularly regarding the exponents in the equations for mass distribution.

Discussion Status

Participants are actively engaging with the original poster's approach, providing corrections and affirmations. There is a focus on ensuring the mathematical expressions are accurate, with some guidance offered regarding the necessary adjustments to the equations.

Contextual Notes

There is an emphasis on the correct formulation of the equations used to calculate the mass distributions, highlighting the importance of precise mathematical representation in the context of the problem.

Cedric Chia
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Homework Statement


Assuming a Salpeter IMF with upper and lower mass limits of 0.1 and 20 M⊙ respectively, calculate:

(i) the mass point at which half the mass formed in a stellar cluster lies in more massive systems and half in less massive systems.

ii) the mass point at which half the luminosity of the star cluster lies in more massive systems and half in less massive systems.

Homework Equations


to find number of stars in the range x and y: fN = ∫xy M -7/3 dM / ∫0.120 M -7/3 dM
to find mass occupied by the starts in the range x and y: fM = ∫xy M -7/3 dM / ∫0.120 M -7/3 dM

The Attempt at a Solution


Question(i) :
using the second equation,
fM = ∫xy M -7/3 dM / ∫0.120 M -7/3 dM
1/2 = ∫x20 M -7/3 dM / ∫0.120 M -7/3 dM
solving for x and we get,
x = 0.5 M⊙
 
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Your two relevant equations look the same but the exponent should be different.
 
mfb said:
Your two relevant equations look the same but the exponent should be different.
yess I'm really sorry I've forgot to put another M in the second equation!

correction:
to find mass occupied by the starts in the range x and y: fM = ∫xy M-7/3 M dM / ∫0.120 M-7/3 M dM
 

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