What is the Correct Calculation for Percentage Yield of Alkene from Alcohol?

[ChemDoodle]

We were preparing Alkene from Alcohol & were asked to calculate percentage yield.
We used 13.5 ml Cyclohexanol with 13.5 ml water & 7ml Sulfuric acid.

To calculate % yield,i need theoretical mass..
So i was calculating no.of moles of cyclohexanol & cyclohexene (the product) to get the theoretical mass.

No of moles of cylcohexanol = m/molar mass
mass = 13.5 ml x 0.926 g/ml (density) = 12.987 g
No.of moles of cyclohexanol = 12.987/100.16 = 0.136 moles

No.of moles of cyclohexne = no.of moles of cyclohexanol = 0.136 moles (from stoichiometry)
Theoretical mass of cyclohexene = n x M
=0.136 x 82.14 = 11.17104 g
Is this calculation correct?

 

[saxen]

We were preparing Alkene from Alcohol & were asked to calculate percentage yield.
We used 13.5 ml Cyclohexanol with 13.5 ml water & 7ml Sulfuric acid.

To calculate % yield,i need theoretical mass..
So i was calculating no.of moles of cyclohexanol & cyclohexene (the product) to get the theoretical mass.

No of moles of cylcohexanol = m/molar mass
mass = 13.5 ml x 0.926 g/ml (density) = 12.987 g
No.of moles of cyclohexanol = 12.987/100.16 = 0.136 moles

Is this calculation correct?

Moreover, i need to calculate no.of moles of cyclohexene..What's the mass of cyclohexene i should take here? Should it be the same as cyclohexanol? Since according to the equation 1mole of cyclohexanol is supposed to yield 1 mole of cyclohexane.

Please help :)

The calculation looks correct. And as you said, next step is to find the number of moles cyclohexene. 1 mole cyclohexanol yield 1 mole cyclohexane, so there are the same numbers of molecules, but you should think about if two molecules have the same molar mass =)

 

[ChemDoodle]

The calculation looks correct. And as you said, next step is to find the number of moles cyclohexene. 1 mole cyclohexanol yield 1 mole cyclohexane, so there are the same numbers of molecules, but you should think about if two molecules have the same molar mass =)

I edited the first post with the continued calculations.Can u check that for me, please?

 

[saxen]

I edited the first post with the continued calculations.Can u check that for me, please?

It looks ok.

 

[ChemDoodle]

Thanku very much :D

 

[saxen]

Thanku very much :D

No problem, you know how to calculate the %yield?

 

[ChemDoodle]

No problem, you know how to calculate the %yield?

Yes :) Actual mass / Theoretical x 100
:D
Thanks for asking,really :) Most helplers here just make me feel inferior lol.