What Is the Correct Equation for a Box on a Frictionless Incline?

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SUMMARY

The correct equation for a box on a frictionless incline involves understanding the forces acting on the box. In this case, a 12 kg box on a 23-degree incline experiences a gravitational force of 117.6 N. The net force equation is represented as Fpull - Fparallel = ma, where Fparallel is calculated using the sine of the incline angle. The correct acceleration, after proper substitution and calculations, is approximately 6.0 m/s², confirming that the sine function is indeed the correct trigonometric function to use in this scenario.

PREREQUISITES
  • Understanding of Newton's second law (Net force = ma)
  • Basic knowledge of trigonometric functions (sine and cosine)
  • Familiarity with gravitational force calculations
  • Concept of forces on inclined planes
NEXT STEPS
  • Review the application of Newton's laws in various physics problems
  • Study the role of trigonometric functions in force calculations on inclined planes
  • Explore examples of frictionless incline problems in physics textbooks
  • Learn about the effects of friction on inclined planes and how to modify equations accordingly
USEFUL FOR

Students preparing for physics exams, particularly those focusing on mechanics and inclined plane problems, as well as educators looking for clear examples of force analysis in frictionless scenarios.

Elo21
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Homework Statement



A 12 kg box is being held on a 23 degree frictionless incline. Find the box's equation once released.


Homework Equations



Net force=ma

Fpull-Fparallel=ma



The Attempt at a Solution



12kg x 9.8m/s = 117.6 N

(Fpull-mgsin23)= ma

sub. known values in

117.6 N-(117.6N (sin23))= 12kg x a

a[tex]\rightarrow[/tex]equals about 6.0 m/s


I know I am doing something wrong. I am reviewing for a final, and am trying to remember things. Please help me figure out what I did wrong.
THANK YOU! :)
 
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i think its cos23 instead of sign.
 

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