What Is the Correct Equation for a Box on a Frictionless Incline?

[Elo21]

Homework Statement

A 12 kg box is being held on a 23 degree frictionless incline. Find the box's equation once released.

Homework Equations

Net force=ma

Fpull-Fparallel=ma

The Attempt at a Solution

12kg x 9.8m/s = 117.6 N

(Fpull-mgsin23)= ma

sub. known values in

117.6 N-(117.6N (sin23))= 12kg x a

a$$\rightarrow$$equals about 6.0 m/s


I know I am doing something wrong. I am reviewing for a final, and am trying to remember things. Please help me figure out what I did wrong.
THANK YOU! :)

 

[dacruick]

i think its cos23 instead of sign.