What is the Correct Equation for Flow Rate?

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foo9008
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Homework Statement


the equation of flow aret given is [(pi)((r_o)^4 ) / 8μ ] [-d/ds (ρ +yz ) ] , but the ans that i got is - [(pi)((r_o)^4 ) / 8μ ] [-d/ds (ρ +yz ) ] , what's wrong with my working ?
Textbook page section 4.4 Laminar Flow in Pipe showing shear stress tau = mu dv/dy = -mu dv/dR = (r/2)[-(d/ds)(p + gamma z)] and the wall coordinate relation y = r_o - r with dv/dr = (dv/dy)(dy/dr) boxed, followed by the result dv/dr = -(r/(2 mu))[-(d/ds)(p + gamma z)].

Printed textbook page with handwritten annotations deriving Poiseuille pipe flow: velocity profile equations 4.14 to 4.16 and the flow rate integral Q = integral of v dA, with a handwritten expansion in the lower part.

Homework Equations

The Attempt at a Solution

 
Try the simpler $$\int_0^{r_0} (r_0^2 -r^2)\, r dr $$to avoid things like the ##r_0^3## (?) in your first step
 
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BvU said:
Try the simpler $$\int_0^{r_0} (r_0^2 -r^2)\, r dr $$to avoid things like the ##r_0^3## (?) in your first step
thanks , i got the ans already