What Is the Correct Theta to Use in Calculating the Scalar Product of Vectors?

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SUMMARY

The discussion focuses on calculating the scalar product of vectors A and B, given specific parameters. Vector B has a magnitude of 5.45 m at an angle of 60°. The scalar products B·A and B·C are provided as 32.4 m² and 35.1 m², respectively. The angle θ used in the equation A·B = MagAxMagBcosθ is clarified to be the angle between vectors A and B, necessitating the introduction of a new variable ψ for the angle of vector A.

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madinsane
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Homework Statement



Let vectorB= 5.45 m at 60°. Let C have the same magnitude as A and a direction angle greater than that of A by 25°. Let B·A = 32.4 m2 and B·C = 35.1 m2. Find the magnitude and direction of A .

Homework Equations



A·B=MagAxMagBcosθ

The Attempt at a Solution


I just have one problem here. What do I use as theta? do i do cos 60?
magnitude of b is 5.45 and that of a is unknown but what about the angle?
thanks
 
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hi madinsane! :smile:
madinsane said:
What do I use as theta? do i do cos 60?
magnitude of b is 5.45 and that of a is unknown but what about the angle?

θ is the angle between the two vectors

you'll have to give the angle of A a name, ψ say, and then the angle of C is ψ + 25° :wink:
 

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