What is the correlation of X and Z in terms of variance and covariance?

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Homework Help Overview

The discussion revolves around the correlation and covariance between two random variables, X and Z, where Z is defined as the difference between independent random variables X and Y. The problem involves calculating the covariance and correlation coefficient based on given variances.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the variance of Z and expresses confusion regarding the covariance between X and Z. They also explore the relationship between the covariance of independent variables.

Discussion Status

Participants are engaging with the mathematical properties of covariance and variance. Some have acknowledged the use of specific laws related to covariance, while others are clarifying their understanding of these concepts. There is an ongoing exploration of how to apply these principles to the problem at hand.

Contextual Notes

The original poster notes a struggle with the problem for several hours and has recognized the independence of X and Y as a relevant factor in their calculations. There is a mention of a double post, indicating a potential misunderstanding of the forum's structure.

CescGoal
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Very sorry that I've double posted but I realized i placed the original post in Precalculus.



1. Homework Statement
Question

Let X and Y be independent random variables with variances 9 and 7 respectively and let
Z = X - Y

a) What is the value of Cov(X,Z)
b) What is the value of the correlation coefficient of X and Z?

I've been stuck on this one question for 2-3 hours; its ridiculous, I know. Here's my terrible try.


3. The Attempt at a Solution
a)

Var(X) = 9
Var(Y) = 7

Var(X-Y) = Var(X) + Var(Y) = Var(Z)
Therefore, Var(Z) = 7 + 9 =16
Cov(X,Z) = E[XZ] - E[X]E[Z]


and b) \rhoXZ = \frac{Cov(X,Z)}{\sqrt{Var(X)*Var(Z)}}



= \frac{Cov(X,Z)}{\sqrt{9}*\sqrt{16}}
= \frac{Cov(X,Z)}{12}

Since last topic, I've realized that Cov(X,Y) = 0 due to independency. But I don't know how to use it.
 
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Cov(X,Z)=Cov(X,X-Y). Cov(X,X-Y)=Cov(X,X)-Cov(X,Y), right?
 


I didn't know about that law; thankyou very much.
 


CescGoal said:
I didn't know about that law; thankyou very much.

It's pretty obvious if you write out the definition of Cov. You should try and do that so you can see why it's true.
 

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