What is the critical angle for light traveling through glass?

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Homework Help Overview

The discussion revolves around determining the critical angle for light traveling through glass, based on the time taken for light to travel specific distances in vacuum and a medium. The subject area includes optics and the principles of refraction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of critical angle and its relationship with the index of refraction. Questions arise about the adequacy of the provided information to determine the index of refraction. Some participants attempt to derive the critical angle using Snell's Law and discuss the implications of their findings.

Discussion Status

The discussion is active, with participants sharing insights and attempting to clarify concepts. Some guidance has been offered regarding the application of Snell's Law and the importance of self-checking results. There is no explicit consensus on the final answer, but various interpretations and approaches are being explored.

Contextual Notes

Participants note that the problem may resemble homework, despite some claiming it is for exam preparation. There is an emphasis on using appropriate forums for such questions, indicating a structured approach to discussion.

narendra
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Light takes "t1" seconds to travel a distance "x" cm in vacuum and same light takes "t2" seconds to travel "10x" cm in a medium.The critical angle for the corresponding medium is .. ??
 
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narendra said:
Light takes "t1" seconds to travel a distance "x" cm in vacuum and same light takes "t2" seconds to travel "10x" cm in a medium.The critical angle for the corresponding medium is .. ??

This sounds like homework.

What is the definition of critical angle? What do you know about the relationship between the critical angle and the index of refraction? Do you have enough information to try to determine the index of refraction in this case?
 
the angle of incidence at which angle of refraction becomes 90 degress is critical angle.(C)
relation is
angle of refraction = 1/sinC
Another thing that i know is refractive index for vacuum is "1"

This is not homework..i am preparing for a competetive exam.
I could not figure out how to solve this problem.
 
Even though this is not literally "homework", it is "homework-like", that is, a specific exercise that you want to find the solution for. By our rules, it belongs in the "Homework and Coursework Help" forums."

You've already received some help with this, so I will move this to the appropriate forum instead of deleting it and asking you to re-post it. Please use the homework forums for similar questions in the future.

(Questions for clarifying concepts are OK in the main forums.)
 
narendra said:
the angle of incidence at which angle of refraction becomes 90 degress is critical angle.(C)
relation is
angle of refraction = 1/sinC
Another thing that i know is refractive index for vacuum is "1"

This is not homework..i am preparing for a competetive exam.
I could not figure out how to solve this problem.

Index?
It's just Snell's Law with the appropriate angles inserted.
Doesn't that equation give you what you want?
If you are still doubtful, it is almost certainly to be found if you Google "Critical Angle Hyperphysics"
If in doubt, always try Hyperphysics first. It has most of the facts and formulae you are likely to need - but it doesn't do your thinking for you. haha
 
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i think i have the Solution

when light travels from denser to rarer medium then,
sin r / sin i = v1 / v2
so from given data,

→sin 90 / sin C = [x/t1]/[10x/t2]
→1/sin C = t2/10t1
→ sin C = 10t1/t2
→ C = arcsin(10t1/t2)

I think this is the right answer,
Please correct me if i am wrong.
 
Go for it.
This is a confidence thing, I think.
What numerical answer do you get for glass?
Does it look reasonable? (It's unlikely to be 'a bit right', isn't it? If it looks OK then it is ok)
Google critical angle values. The exercise will do you good. Get used to self checking.
 

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